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CBSE Class 10 Answered

A 2cm tall object at a distance of 15cm is placed perpendicular to the principal axis of a lens of focal length 10cm. If it forms an image of double of its size, find the possible positions of image?
Asked by | 05 Mar, 2013, 06:16: PM
answered-by-expert Expert Answer
m= magnification=2=v/u    v=2u     now put in lens formula and solve:
v=2x(-15)=-30 cm
size of image:
I/O=2
I=4cm
Answered by | 06 Mar, 2013, 04:52: PM

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