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CBSE Class 12-science Answered

The electric field E due to any point charge near it is defind E=lim f/q where q is the test charge. what is the physical significance of taking limit tends to zero in this expression ? Draw the electric field lines of point charge when Q>0 and Q<0.  
Asked by aksingh8080 | 04 Jul, 2018, 09:32: PM
answered-by-expert Expert Answer
When there is a charge or charge distribution in a given region,
test charge q placed at some point in the given region experiences the electrostatic forceas per coulomb's law.
This force divideded by test charge (force per unit charge) is defiened as the electrical field at this point.
But this test charge should not alter the true field due to it's own charge. This is possible if test charge has
high magnitude of charge. Hence electric field is measured by a small magnitude of test charge (q → 0).
 
Field lines for point charge q, for both the sighs,  are shown in the figure given below

 

Answered by Thiyagarajan K | 05 Jul, 2018, 09:33: AM

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