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CBSE Class 7 Answered

Respected sir/mam,
There is a maths application based question that is troubling me can you please me how to solve with its answer
The question follows:

Sara is in the process of making ice cream. She has heated all the ingredients to 40 °C and put them in refrigerator to freeze. If the cooling rate is 9 °C per hour, what will be the temperature in freezer after 12 hours?

Asked by ranksahoo | 11 May, 2017, 01:11: PM
answered-by-expert Expert Answer
begin mathsize 16px style All space the space ingredients space are space heated space to space 40 space degree straight C space and space put space in space straight a space refrigerator space to space freeze. space
Given space that space the space cooling space rate space is space 9 space degree straight C space per space hour.
That space means space for space after space every space hour comma space the space temperature space will space reduce space by space 9 space degree straight C.
So comma space after space 12 space hours comma space the space temperature space will space reduce space by space 12 cross times 9 space degree straight C equals 108 degree straight C
Thus comma space the space temperature space after space 12 space hours equals space 40 space degree straight C minus 108 degree straight C equals negative 68 degree straight C
end style
Answered by Rebecca Fernandes | 24 Nov, 2017, 12:39: PM

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