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Home / Doubts and Solutions/JEE/Physics

Que 10 and 11

Asked by Umesh 25th October 2017, 4:45 PM
Answered by Expert
Answer:
Question 11)
 
 
Let the hieght of tower be H=AB
Normal at point C bisect the 90 degree angle
therefore angle ACB = CAB = 45 degree because tower is at right angle with ground.
 
tan theta equals fraction numerator A B over denominator C B end fraction  (Angle ACB)
tan space 45 space equals space H over 60
H = 60 m
 
 
Note:- Please question other question separately. Only one question at a time can be answered.
Answered by Expert 5th December 2017, 7:17 PM
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