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Asked by rickykumar00001 | 19 Feb, 2016, 08:08: PM
Expert Answer
Molar mass of CaCO3 = 100 g (40+12+48)
In 100 g CaCO3, 12 g Carbon is present.
That means 12 % carbon is present in CaCO3.
So in 55% pure sample, 55x12/100 = 6.6% carbon is present.
Answered by Prachi Sawant | 21 Feb, 2016, 02:34: PM
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