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  In an experiment of simple pendulum time period measured was 50 sec for 25 vibrations when the length of the simple pendulum was taken 100 cm. If the least count of stop watch is 0.1 sec. and that of meter scale is 0.1 cm then maximum possible error in value of g is :- (1) 0.5 % (2) 1 % (3) 0.4 % (4) 0.1 %
Asked by devanshmalhotra2609 | 07 Jan, 2016, 06:17: PM
answered-by-expert Expert Answer

Hi Devansh,

begin mathsize 14px style straight T equals 2 straight pi square root of straight l over straight g end root therefore straight g equals fraction numerator 2 πl over denominator straight T squared end fraction therefore Δg over straight g cross times 100 equals Δl over straight l cross times 100 plus 2 ΔT over straight T cross times 100 therefore Δg over straight g cross times 100 equals fraction numerator 0.1 over denominator 100 end fraction cross times 100 plus 2 cross times fraction numerator 0.1 over denominator 50 end fraction cross times 100 therefore Δg over straight g cross times 100 equals 0.1 plus 0.4 equals 0.5 percent sign Hence comma space the space maximum space possible space error space in space the space measurement space of space straight g space is space 0.5 percent sign. end style

Answered by | 07 Jan, 2016, 06:29: PM
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