CBSE Class 12-science Answered

How to find value of sine inverse of sin 10 ............show answer through proper steps

Asked by Farooq Ahmad Shah | 28 Jan, 2016, 12:40: AM

Expert Answer

sin to the power of negative 1 end exponent open parentheses sin theta close parentheses equals theta comma space w h e n space theta element of open square brackets negative pi over 2 comma pi over 2 close square brackets H e r e space w e space h a v e space t o space f i n d space sin to the power of negative 1 end exponent open parentheses sin 10 close parentheses 10 not an element of open square brackets negative pi over 2 comma pi over 2 close square brackets sin to the power of negative 1 end exponent open parentheses sin 10 close parentheses equals sin to the power of negative 1 end exponent open parentheses sin open parentheses 3 pi minus 10 close parentheses close parentheses space space left parenthesis because sin open parentheses 3 straight pi minus straight theta close parentheses equals sin theta right parenthesis W e space u s e d space t h e space s u b s t i t u t i o n space 3 pi minus 10 space b e c a u s e space i t space i s space b e t w e e n space open square brackets negative pi over 2 comma pi over 2 close square brackets open curly brackets 3 pi less than 10 less than 3 pi plus pi over 2 rightwards double arrow 3 pi less than 10 less than fraction numerator 7 pi over denominator 2 end fraction rightwards double arrow negative fraction numerator 7 pi over denominator 2 end fraction less than negative 10 less than negative 3 pi space left parenthesis m u l t i p l y i n g space b y space minus 1 space r e v e r s e s space t h e space i n e q u a l i t y right parenthesis rightwards double arrow negative fraction numerator 7 pi over denominator 2 end fraction plus 3 pi less than 3 pi minus 10 less than negative 3 pi plus 3 pi space left parenthesis a d d i n g space 3 pi space t o space a l l right parenthesis rightwards double arrow negative pi over 2 less than 3 pi minus 10 less than 0 close curly brackets S o space s i n to the power of negative 1 end exponent open parentheses s i n 10 close parentheses equals s i n to the power of negative 1 end exponent open parentheses s i n open parentheses 3 pi minus 10 close parentheses close parentheses equals 3 pi minus 10

Answered by Vijaykumar Wani | 28 Jan, 2016, 12:31: PM

CBSE Class 12-science Answered

Concept Videos

Properties of Inverse Trigonometry Part - 1

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Problem-solving on inverse trigonometric applications ...

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CBSE Class 12-science Answered

Concept Videos

Properties of Inverse Trigonometry Part - 1

Properties of Inverse Trigonometry Part - 2

Problem-solving on inverse trigonometric applications ...

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