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CBSE Class 11-science Answered

Emperical formula of a gaseous compound is CH2Cl. 0.12 g of the compound occupies a volume of 37.20cc at 105 degree centigrade and 768mm Hg.Find the molecular formula of the compound.
Asked by tps.mjmdr | 22 Jun, 2018, 06:36: PM
answered-by-expert Expert Answer
Given:
 
Empirical formula = CH2Cl
 
Empirical formula weight = 49.5
 
Weight of substance= 0.12 g 
 
Volume = 37.20cc
 
Temprature, T = 105 ºC
 
Pressure, P = 768mm
 
We space have comma PV space equals space nRT PV space equals space straight w over straight m RT fraction numerator 768 cross times 37.24 space over denominator 760 cross times 1000 end fraction equals fraction numerator 0.12 over denominator straight m end fraction cross times 0.0821 cross times 378 space space space space space space space space space space space space straight m equals space 100 Empirical space formula equals space CH subscript 2 Cl Empirical space formula space weight space equals 49.5 straight n equals space fraction numerator molar space mass over denominator empirical space formula space weight end fraction space space space space space equals fraction numerator 100 over denominator 49.5 end fraction straight n almost equal to space 2 Molecular space formula space equals space left parenthesis CH subscript 2 Cl right parenthesis subscript 2
Molecular formula of the compound is C2H4Cl2.
Answered by Varsha | 24 Jun, 2018, 06:37: PM

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