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Dear Sir/Ma'am pl tell the above  example 21

Asked by neeraj.unnao 4th October 2017, 9:01 AM
Answered by Expert
Answer:
begin mathsize 16px style From space the space given space line space we space can space see space that space directions space of space straight x comma space straight y comma space straight z space axis space is space 1 space respectively. space Also
for space the space second space equation space directions space are space 2 comma space 1 comma space 1.
Hence comma space we space have space taken space constant space for space the space first space equation space as space straight t space and space for space second space
equation space as space straight s.
Then space equating space with space the space constants space we space get space straight P space left parenthesis straight t comma space straight t space minus space straight a comma space straight t right parenthesis space and space any space point space on space the
similarly space straight Q space left parenthesis space 2 straight s space minus space straight a comma space straight s comma space straight s right parenthesis
We space have space taken space direction space numbers space on space the space line space PQ space by space subtracting space coordinates
of space straight Q space and space coordinates space of space straight P.
But space it space is space given space that space direction space numbers space of space teh space line space PQ space are space 2 comma space 1 comma space 2
Hence comma space equation space of space the space line space
fraction numerator 2 straight s space minus space straight a space minus space straight t over denominator 2 end fraction space equals space fraction numerator straight s space minus space straight t space plus space straight a over denominator 1 end fraction space equals space fraction numerator straight s space minus space straight t space over denominator 2 end fraction
Equating space fraction numerator 2 straight s space minus space straight a space minus space straight t over denominator 2 end fraction space equals space space fraction numerator straight s space minus space straight t space over denominator 2 end fraction space and space fraction numerator straight s space minus space straight t space plus space straight a over denominator 1 end fraction space equals space fraction numerator straight s space minus space straight t space over denominator 2 end fraction
After space solving space we space get space straight s space equals space straight a space and space straight t space equals space 3 straight a
using space straight t space equals space 3 straight a space gives space point space straight P space and space straight s space equals space straight a space gives space point space straight Q space that space are
points space of space intersection. space end style
Answered by Expert 27th December 2017, 5:43 PM
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