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CBSE Class 8 Answered

By selling two tables for ₹1200 each,a man gains 10% on one and losses 10% on the other. Find the gain or loss percent in the whole transaction.
Asked by Shawn | 09 Mar, 2016, 11:16: PM
answered-by-expert Expert Answer
Given, 
SP of 1 table = Rs.1200
profit% = 10 
CP = fraction numerator 100 over denominator 100 plus P percent sign end fraction cross times S P
= fraction numerator 100 over denominator 100 plus 10 end fraction cross times 1200
= 100 over 110 cross times 1200
CP = 1090.90
 
 
Loss = 10%
CP = fraction numerator 100 over denominator 100 minus L percent sign end fraction cross times S P
= fraction numerator 100 over denominator 100 minus 10 end fraction cross times 1200
= 100 over 90 cross times 1200
CP = 1333.33
 
Total CP of 2 tables = 1090.90 + 1333.33 = Rs.2424.23
 
Total SP of 2 tables = 1200 × 2 = Rs.2400
 
CP > SP, so a loss is incurred
 
Loss = CP - SP 
= 2424.23 - 2400
=Rs.24.23
 
Loss% = fraction numerator L cross times 100 over denominator C P end fraction
= fraction numerator 24.23 cross times 100 over denominator 2424.23 end fraction
= 0.99 approximately equal to 1%
Hence, a loss of approximately 1% was incurred. 
Answered by Keravi Thanani | 10 Mar, 2016, 11:37: AM

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