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CBSE Class 9 Answered

A semi circular sheet of metal of diameter 28 cm is bent into an open conical cup. Find the depth and capacity of cup.
Asked by dimplesharma0810 | 05 Mar, 2016, 10:04: AM
answered-by-expert Expert Answer
Diameter space of space the space circular space sheet space is space 28 space cm. Radius space equals space 14 cm. Circumference space of space semicircular space sheet space equals space 14 straight pi. Now space the space semicircular space sheet space is space bent space into space an space open space conical space cup. Slant space height space of space conical space cup space equals straight l space equals space radius space of space circular space sheet space equals space 14 space cm circumference space of space the space base space of space conical space cup space equals space Circumference space of space semicircular space sheet 2 πR space equals space 14 straight pi straight R space equals space 7 cm Depth space of space conicap space cup space equals space Height space of space cone space equals space square root of straight l squared minus straight r squared end root equals square root of open parentheses 14 close parentheses squared minus open parentheses 7 close parentheses squared end root equals square root of 196 minus 49 end root equals square root of 147 space space equals space 7 square root of 3 cm Capacity space of space conical space cup space equals space Volume space of space space equals space 1 third πR squared straight h space equals space 1 third cross times 22 over 7 cross times 7 squared cross times 7 square root of 3 equals fraction numerator 1078 square root of 3 over denominator 3 end fraction cm cubed
Answered by Vijaykumar Wani | 07 Mar, 2016, 10:45: AM

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