ICSE Class 9 Answered
A cyclist driving at 36 km/h stops in 2s by the application of brakes.Calculate : (1) retardation (2) distance covered during application of brakes ?
Asked by Vikas | 23 May, 2018, 12:20: AM
Expert Answer
Equations are to be applied is "v = u - a×t " and "S = u×t - (1/2)×a×t2 "
v is final velocity, u initial velocity, a is retardation, S is distance travelled and t is time.
initial velocity = 36 km/h ×(5/18) = 10 m/s
(1) retardation :- 0 = 10-a×2 , solving for a we get retardation a = 5 m/s2
(2) distance :- S = 10×2 -(1/2)×5×4 = 10 m
Answered by Thiyagarajan K | 23 May, 2018, 11:14: AM
Application Videos
Concept Videos
ICSE 9 - Physics
Asked by thesangeeta1990 | 08 Mar, 2024, 04:37: PM
ANSWERED BY EXPERT
ICSE 9 - Physics
Asked by navyaindu48 | 21 Sep, 2023, 07:57: PM
ANSWERED BY EXPERT
ICSE 9 - Physics
Asked by krashish57 | 14 Sep, 2023, 11:05: AM
ANSWERED BY EXPERT
ICSE 9 - Physics
Asked by rishil23dec | 08 Aug, 2023, 09:31: PM
ANSWERED BY EXPERT
ICSE 9 - Physics
Asked by anshumancharanpahadi | 13 May, 2023, 05:58: PM
ANSWERED BY EXPERT
ICSE 9 - Physics
Asked by mymunathabasum1 | 24 Apr, 2023, 06:06: PM
ANSWERED BY EXPERT
ICSE 9 - Physics
Asked by snehakarmakar040 | 16 Apr, 2023, 11:53: AM
ANSWERED BY EXPERT
ICSE 9 - Physics
Asked by madhupandey6555 | 05 Jan, 2023, 05:36: PM
ANSWERED BY EXPERT