A block of mass m is pulled on the smooth horizontal surface with the help of two ropes each of mass m, connected to the opposite faces of the block. The forces on the ropes are F and 2F. The pulling force on the block is
Asked by m.nilu
16th July 2018,
10:00 PM
Answered by Expert
Answer:
net force acting towards right side is (2F-F) = F
accceleration produced for the whole system, a = F/(3m)
Tension in the right side of rope pulling the block. Since the mass of the block is m and it moves with acceleration F/(3m),
Tension in the rope or pulling force of the block = m×F/(3m) = F/3
Answered by Expert
17th July 2018,
12:04 PM
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