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CBSE Class 11-science Answered

9th?
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Asked by smanishkumar2002 | 04 Aug, 2018, 05:37: AM
answered-by-expert Expert Answer
Given:
 
P = 50 atm
 
V = 25 litre
 
n= 10 moles
 
a= 5.46 atm
 
b= 0.031 lit/mol
 
We konw, for n moles of gas,
 
open square brackets straight P space plus fraction numerator straight n to the power of blank squared end exponent straight a over denominator straight V squared end fraction close square brackets open square brackets straight V minus nb close square brackets space equals nRT open square brackets 50 plus fraction numerator open parentheses 10 close parentheses squared 5.46 over denominator open parentheses 25 close parentheses squared end fraction close square brackets open square brackets 25 minus open parentheses 10 cross times 0.031 close parentheses close square brackets equals space 10 cross times 0.0821 cross times straight T straight T space equals 1529.9 space straight K straight T space equals space 1256.9 space to the power of ring operator straight C
Temperature of gas is 1256.9 °C.
Answered by Varsha | 05 Aug, 2018, 04:07: PM

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