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CBSE Class 11-science Answered

9?
Asked by smanishkumar2002 | 10 Jun, 2018, 10:50: PM
answered-by-expert Expert Answer
The direction of applied force and gravitational forces of blocks are shown in figure . All these forces are parallel to inclined plane.
 
It is required to get acceleration 2 m/s2. Hence we have
 
F - (3g+2g+5g)sin30º = (3+2+5)×2
 
F = (3+2+5)×(2+gsin30º) = (3+2+5)×6.9 = 69 N
 
Contact force between m1 and m2 = m1×2 = 3×2 = 6N
Contact force between m2 and m3 = (m1+m2)×2 = 5×2 = 10N
Answered by Thiyagarajan K | 11 Jun, 2018, 10:33: AM
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