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CBSE Class 11-science Answered

6th?
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Asked by smanishkumar2002 | 04 Aug, 2018, 05:37: AM
answered-by-expert Expert Answer
Given:
 
T =20 °C
 
  =293 K
 
P = 82 cmHg
 
We space have comma straight mu subscript rms space equals square root of fraction numerator 3 RT over denominator straight M end fraction end root where comma straight R space equals 8.314 space straight K to the power of negative 1 end exponent mol to the power of minus straight M equals space 0.048 space kg divided by mol straight mu subscript rms space equals square root of fraction numerator 3 open parentheses 8.314 close parentheses open parentheses 293 close parentheses over denominator 0.048 end fraction end root straight mu subscript rms equals space 390.3 space straight m divided by straight s
 
Answered by Varsha | 05 Aug, 2018, 03:24: PM

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CBSE 11-science - Chemistry
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