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CBSE Class 11-science Answered

5.17 sum plz
question image
Asked by lovemaan5500 | 26 Jan, 2019, 12:55: PM
answered-by-expert Expert Answer
We have,
 
Meq. of AgCl = Meq. of HCl = milli mole of HCl space space fraction numerator PV over denominator RT cross times 10 cubed end fraction
 
 
fraction numerator straight w over denominator mol space wt space of space AgCl end fraction cross times 1000 space equals space fraction numerator 750 cross times 10 over denominator 760 cross times 100 end fraction cross times fraction numerator 10 squared over denominator 0.0821 cross times 285 end fraction space space space space space space space space space space space fraction numerator begin display style straight w end style over denominator begin display style 143.5 end style end fraction cross times 1000 space equals space fraction numerator 9.868 over denominator 0.0821 cross times 285 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space straight w space equals fraction numerator 0.4217 cross times 143.6 over denominator 1000 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 60.52 over denominator 1000 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 0.06052 space straight g
The weight of AgCl is 0.06052 g.
 
 
Answered by Varsha | 28 Jan, 2019, 10:58: AM

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