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5.0g of an ideal gas occupies 9.2 L at STP. What volume would it occupy at 120°C and 92 mm Hg?

Asked by Topperlearning User 20th April 2015, 1:04 PM
Answered by Expert
Answer:

PV = nRT

At STP, P = 760mm Hg, T = 273 K

P1 = 760 mm

V1 = 9.2L

T1= 273K

P1= 92 mm

V2 = ?

T2 = 120 + 273 = 393K

Using relation:

begin mathsize 11px style fraction numerator straight P subscript 1 straight V subscript 1 over denominator straight T subscript 1 end fraction space equals space fraction numerator straight P subscript 2 straight V subscript 2 over denominator straight T subscript 2 end fraction
fraction numerator 760 space straight X space 9.2 over denominator 273 end fraction space equals space fraction numerator 92 space straight X space straight V 2 over denominator 393 end fraction
straight V subscript 2 space equals space fraction numerator 760 space straight X space 9.2 space straight X space 393 over denominator 273 space straight X space 92 end fraction space
straight V subscript 2 space equals space 109 space straight L end style

 

Answered by Expert 20th April 2015, 3:04 PM
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