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CBSE Class 11-science Answered

4th term
question image
Asked by lovemaan5500 | 12 Jul, 2018, 10:10: PM
answered-by-expert Expert Answer
begin mathsize 16px style open parentheses fraction numerator 3 straight x squared over denominator 2 end fraction minus fraction numerator 1 over denominator 3 straight x end fraction close parentheses to the power of 9
straight T subscript straight n plus 1 end subscript equals straight C presuperscript 9 subscript straight r open parentheses 3 over 2 straight x squared close parentheses to the power of 9 minus straight r end exponent open parentheses fraction numerator negative 1 over denominator 3 straight x end fraction close parentheses to the power of straight r equals straight C presuperscript 9 subscript straight r 3 to the power of 9 minus 2 straight r end exponent over 2 to the power of 9 minus straight r end exponent space straight x to the power of 18 minus 3 straight r end exponent
for space the space coeff space of space term space independent space of space straight x space we space need space straight x to the power of 0 comma space straight x to the power of negative 1 end exponent comma space straight x to the power of negative 2 end exponent
For space straight x to the power of 0 comma space 18 space minus space 3 straight r space equals 0 comma space straight r equals 6
For space straight x to the power of negative 1 end exponent comma space 18 space minus space 3 straight r space equals negative 1 comma space straight r equals 19 over 3..... not space possible
For space straight x to the power of negative 2 end exponent comma space 18 space minus space 3 straight r space equals negative 2 comma space straight r equals 20 over 3..... not space possible
therefore straight r equals 6
straight C presuperscript 9 subscript 6 3 to the power of 9 minus 12 end exponent over 2 to the power of 9 minus 6 end exponent equals 7 over 18


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Answered by Arun | 16 Jul, 2018, 04:02: PM

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