CBSE Class 10 Answered

Dear Student,

Let cost of each chair = Rs. x

and cost of each table = Rs. y

According to the statement, 4 chairs and 3 tables cost Rs. 2100

4 × (cost of one chair) + 3 × (cost of one table) = Rs. 2100

So, we get an equation

4x + 3y = 2100   ……...... (i)

Also, 5 chairs and 2 tables cost Rs.1750

So we get another equation

5x + 2y = 1750 ……….. (ii)

We will solve equations (i) and (ii) to get the answer

Let us solve the two equations using elimination method

2 × equation (i) gives

8x + 6y = 4200  ………………………… (A)

And 3 × equation (ii) gives

15x + 6y = 5250 ……………………….. (B)

Subtracting (A) from (B), we get

15x + 6y – 8x – 6y = 5250 – 4200

7x = 1050

So   x = 150

Substituting this value of x in equation (ii), we get

   5(150) + 2y = 1750

   750 + 2y = 1750

   2y = 1750 – 750

   2y = 1000

So   y = 500

Hence,   cost of each chair = Rs. 150

and        cost of each table = Rs. 500

Regards

Team

Topper Learning