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CBSE Class 12-science Answered

4.37 numerical plz
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Asked by lovemaan5500 | 06 Jan, 2020, 03:33: PM
answered-by-expert Expert Answer
Given:
 
Initial concentration [a0] = 50 mol/L 
 
Concentration after time t, [a] = 0.05 mol/L
 
Rate constant, k = 6 min 
 
t = ?
 
Using Rate equation for first order:
 
straight k space equals space fraction numerator 2.303 over denominator straight t end fraction log fraction numerator open square brackets straight a subscript 0 close square brackets over denominator open square brackets straight a close square brackets end fraction

straight t space equals space fraction numerator 2.303 over denominator straight k end fraction log fraction numerator open square brackets straight a subscript 0 close square brackets over denominator open square brackets straight a close square brackets end fraction

straight t space equals fraction numerator 2.303 over denominator 6 end fraction log fraction numerator 50 over denominator 0.05 end fraction

space space equals space fraction numerator 2.303 over denominator 6 end fraction cross times 3

straight t space equals space 1.15 space min
 
Answered by Varsha | 07 Jan, 2020, 11:36: AM
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