CBSE Class 11-science Answered
4?
Asked by smanishkumar2002 | 05 Jun, 2018, 10:11: PM
Expert Answer
let us take g = 10 m/s2
Vertical height reached for every upward motion =:- h = u2/(2g) = (20×20)/(2×10) = 20 m
time for reaching maximum height :- t = u/g = 20/10 = 2 s
Answered by Thiyagarajan K | 06 Jun, 2018, 02:31: PM
CBSE 11-science - Physics
Asked by sumedhasingh238 | 28 Mar, 2024, 11:10: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by roshnibudhrani88 | 23 Mar, 2024, 05:52: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by emad.amd | 21 Mar, 2024, 12:00: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by vinitdubey7735 | 14 Mar, 2024, 11:21: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by om636694 | 04 Mar, 2024, 09:10: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by rajuinwati12 | 04 Mar, 2024, 09:22: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by rosysahu678 | 02 Mar, 2024, 06:09: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by vaddevenkatesulu56 | 26 Feb, 2024, 09:02: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by rustampathan | 25 Feb, 2024, 06:39: PM
ANSWERED BY EXPERT