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Home / Doubts and Solutions/ICSE/Class 11 Science/Physics

35th ques plz

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Asked by lovemaan5500 25th September 2018, 6:59 PM
Answered by Expert
Answer:
Centripetal force to the revolving planet around sun is provided by gravitational force.
 
Hence begin mathsize 12px style fraction numerator G cross times M cross times m over denominator R squared end fraction space equals space m cross times omega squared cross times R space space equals space m cross times fraction numerator 4 pi squared over denominator T squared end fraction cross times R space space........................ left parenthesis 1 right parenthesis end style
where G is gravitatationalconstant, M is mass of sun , m is mass of planet,
R is mean distance between sun and planet and ω is angular speed of revolution
and T is period of revolution around sun.
 
from eqn.(1), we can write begin mathsize 12px style R space proportional to space T to the power of bevelled 2 over 3 end exponent space.................... left parenthesis 2 right parenthesis end style
Hence begin mathsize 12px style R subscript V space equals space R subscript E cross times open parentheses fraction numerator 224.7 over denominator 365.3 end fraction close parentheses to the power of bevelled 2 over 3 end exponent space equals space 1.496 cross times 10 to the power of 8 cross times open parentheses fraction numerator 224.7 over denominator 365.3 end fraction close parentheses to the power of bevelled 2 over 3 end exponent space equals space 1.082 cross times 10 to the power of 8 space k m end style
RV and RE are mean distances from sun for Venus and Earth respectively
 
similarly
begin mathsize 12px style R subscript M space equals space R subscript E cross times open parentheses fraction numerator 687 over denominator 365.3 end fraction close parentheses to the power of bevelled 2 over 3 end exponent space equals space 1.496 cross times 10 to the power of 8 cross times open parentheses fraction numerator 687 over denominator 365.3 end fraction close parentheses to the power of bevelled 2 over 3 end exponent space equals space 2.279 cross times 10 to the power of 8 space k m end style
RM is mean distance of Mars from sun
Answered by Expert 26th September 2018, 8:46 AM
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