Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Enquiry

10:00 AM to 7:00 PM IST all days.

Business Inquiry (North)

Business Inquiry (West / East / South)

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

022-62211530

Mon to Sat - 10 AM to 7 PM

35th ques plz

qsnImg
Asked by lovemaan5500 25th September 2018, 6:59 PM
Answered by Expert
Answer:
Centripetal force to the revolving planet around sun is provided by gravitational force.
 
Hence begin mathsize 12px style fraction numerator G cross times M cross times m over denominator R squared end fraction space equals space m cross times omega squared cross times R space space equals space m cross times fraction numerator 4 pi squared over denominator T squared end fraction cross times R space space........................ left parenthesis 1 right parenthesis end style
where G is gravitatationalconstant, M is mass of sun , m is mass of planet,
R is mean distance between sun and planet and ω is angular speed of revolution
and T is period of revolution around sun.
 
from eqn.(1), we can write begin mathsize 12px style R space proportional to space T to the power of bevelled 2 over 3 end exponent space.................... left parenthesis 2 right parenthesis end style
Hence begin mathsize 12px style R subscript V space equals space R subscript E cross times open parentheses fraction numerator 224.7 over denominator 365.3 end fraction close parentheses to the power of bevelled 2 over 3 end exponent space equals space 1.496 cross times 10 to the power of 8 cross times open parentheses fraction numerator 224.7 over denominator 365.3 end fraction close parentheses to the power of bevelled 2 over 3 end exponent space equals space 1.082 cross times 10 to the power of 8 space k m end style
RV and RE are mean distances from sun for Venus and Earth respectively
 
similarly
begin mathsize 12px style R subscript M space equals space R subscript E cross times open parentheses fraction numerator 687 over denominator 365.3 end fraction close parentheses to the power of bevelled 2 over 3 end exponent space equals space 1.496 cross times 10 to the power of 8 cross times open parentheses fraction numerator 687 over denominator 365.3 end fraction close parentheses to the power of bevelled 2 over 3 end exponent space equals space 2.279 cross times 10 to the power of 8 space k m end style
RM is mean distance of Mars from sun
Answered by Expert 26th September 2018, 8:46 AM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Free related questions

26th November 2017, 5:18 PM

Chat with us on WhatsApp