300ml N2(80%pure) reacta with 300ml H2(50% pure) to form NH3 and volume becomes 550ml.Calculate the volume of NH3 produced
Asked by astutijoshi
28th March 2020,
5:08 PM
Answered by Expert
Answer:
the given reactio is,
N2 + 3H2 → 2NH3
at, t = 0 300 ml 300 ml 0 ml
at, t= t 300-x 300-3x 2x
As the volume and temperatue of the gas is assume to be connstant, number of moles directly proportional to volume of gas.
Now,
Final volume, Vf = 550 ml
VN2 + VH2 + VNH3 = 550 ml
(300-x) + (300-3x) + 2x =550
600 -2x = 550
2x = 50
2x is volume of NH3 produced.
Therefore, volume of NH3 produced is 50 ml.
Answered by Expert
29th March 2020,
3:00 PM
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