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3

Asked by rbhatt16 7th December 2017, 9:10 PM
Answered by Expert
Answer:
begin mathsize 16px style 1 plus cosx plus cos 2 straight x plus sinx plus sin 2 straight x plus sin 3 straight x equals 0
1 plus cosx plus cos 2 straight x plus sinx plus sin 3 straight x plus sin 2 straight x equals 0
1 plus cosx plus 2 cos squared straight x minus 1 plus 2 sin 2 xcosx plus sin 2 straight x equals 0 space space space space space space space space space space using space sinC plus sinD equals 2 sin fraction numerator straight C plus straight D over denominator 2 end fraction cos fraction numerator straight C minus straight D over denominator 2 end fraction
cosx plus 2 cos squared straight x plus 2 sin 2 xcosx plus sin 2 straight x equals 0
cosx left parenthesis 1 plus 2 cosx right parenthesis plus sin 2 straight x left parenthesis 2 cosx plus 1 right parenthesis equals 0
left parenthesis 2 cosx plus 1 right parenthesis left parenthesis cosx plus sin 2 straight x right parenthesis equals 0
left parenthesis 2 cosx plus 1 right parenthesis open parentheses cosx plus 2 sinxcosx close parentheses equals 0
cosx left parenthesis 2 cosx plus 1 right parenthesis left parenthesis 1 plus 2 sinx right parenthesis equals 0
Using space given space condition
straight pi over 2 less than open vertical bar 3 straight x minus straight pi over 2 close vertical bar less or equal than straight pi
rightwards double arrow straight pi over 2 less than open parentheses 3 straight x minus straight pi over 2 close parentheses less or equal than straight pi space space space or space space space straight pi over 2 less than negative open parentheses 3 straight x minus straight pi over 2 close parentheses less or equal than straight pi
Solving space both space you space will space get space two space solution space straight x equals straight pi over 2 space and space straight x equals fraction numerator negative straight pi over denominator 6 end fraction end style
Answered by Expert 8th December 2017, 9:40 AM
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