CBSE Class 11-science Answered
3 identical blocks of 2kg are drawn by a force of 10.2N with an acceleration of 0.6m/s2 . Calculate the tension between the blocks B & c
Asked by Sumitradharagaon | 27 Jul, 2019, 09:09: PM
Expert Answer
Acelerating force (3×2×0.6 ) = 3.6 N is very much less than applied force 10.2 N .
Hence friction forces are acting against the movement of blocks.
Let us assume equal friction force f acting on each block in the direction opposite to the movement as shown in figure.
For Block-A :- F - TAB - f = m×a ..................(1)
For Block-B :- TAB - TBC - f = m×a ..................(2)
For Block-C :- TBC - f = m×a .........................(3)
if we add eqn.(1), eqn.(2) and eqn.(3), we get, F - 3 f = 3(m×a)
Hence friction force f = (F/3) - (m×a) = (10.2/3) - ( 2×0.6) = 2.2 N
from eqn.(3), we get, TBC = m×a + f = 2×0.6 + 2.2 = 3.4 N
Answered by Thiyagarajan K | 27 Jul, 2019, 11:09: PM
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