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3 capacitors of capacitances in the ratio 1:2:3 are connected in parallel .their effective capacitance in parallel is greater than that in series by 60/11 pF.calculate the individual capacitances.

Asked by Renu Mariam John 1st March 2013, 7:53 PM
Answered by Expert
Answer:
(C+2C+3C)-6C/11  =60/11
C=1
so the indiv cap are:1pF,2pF and 3 pF
Answered by Expert 4th March 2013, 6:05 PM
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