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CBSE Class 11-science Answered

|2x-1|/|x-1|>2  
Asked by msmamtasingh48 | 20 May, 2019, 08:49: PM
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begin mathsize 18px style open vertical bar fraction numerator 2 x space minus space 1 over denominator x space minus space 1 end fraction close vertical bar greater than 2 rightwards double arrow fraction numerator 2 x space minus space 1 over denominator x space minus space 1 end fraction space greater than space 2 space or space fraction numerator 2 straight x space minus space 1 over denominator straight x space minus space 1 end fraction less than space minus 2 fraction numerator 2 straight x space minus space 1 over denominator straight x space minus space 1 end fraction space minus space 2 space greater than space 0 rightwards double arrow fraction numerator space 2 straight x space minus space 1 space minus space 2 straight x space plus space 2 over denominator straight x space minus space 1 end fraction greater than space 0 rightwards double arrow space fraction numerator 1 over denominator straight x space minus space 1 space end fraction greater than space 0 rightwards double arrow space straight x space minus space 1 space greater than 0 rightwards double arrow straight x space greater than space 1 space space... space left parenthesis straight i right parenthesis fraction numerator 2 straight x space minus space 1 over denominator straight x space minus space 1 end fraction less than space minus 2 rightwards double arrow space fraction numerator 2 straight x space minus space 1 over denominator straight x space minus space 1 end fraction space plus space 2 space less than 0 rightwards double arrow fraction numerator 2 straight x space minus space 1 space plus space 2 straight x space minus space 2 over denominator straight x space minus space 1 end fraction space less than space 0 rightwards double arrow fraction numerator 4 straight x space minus space 3 over denominator straight x space minus space 1 end fraction less than 0 rightwards double arrow fraction numerator 4 open parentheses straight x space minus space begin display style 3 over 4 end style close parentheses over denominator straight x space minus space 1 end fraction less than 0 1 st space condition colon space straight x space less than space 3 over 4 space and space straight x space greater than space 1 In space this space we space will space not space get space any space intersection space point. 2 nd space condition colon space straight x space greater than space 3 over 4 space and space straight x space less than space 1 straight x space element of space open parentheses 3 over 4 comma space 1 close parentheses space space space.... space left parenthesis ii right parenthesis From space left parenthesis straight i right parenthesis space and space left parenthesis ii right parenthesis comma space we space get straight x element of space open parentheses 3 over 4 comma space infinity close parentheses space minus space open curly brackets 1 close curly brackets end style
Answered by Yasmeen Khan | 21 May, 2019, 10:35: AM

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CBSE 11-science - Maths
in exercise 1.3 1st q ii part abc is not subset of bcd but two elements are common i.e bc but in 2 question same exercise i part ab is subset of  bca how ??  
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CBSE 11-science - Maths
Question no 21
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CBSE 11-science - Maths
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CBSE 11-science - Maths
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Asked by naiduuofficial | 06 Jan, 2023, 07:49: PM
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CBSE 11-science - Maths
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Asked by anjaneyagadgil04 | 05 Jan, 2023, 12:16: PM
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CBSE 11-science - Maths
if u = [2,3,4.....,11] A=[2,4,7] B = [ 3,5,7,9,11] C =[7,8,9,10,11] COMPUTE 1] [A INTERSECTION U} intersection {BUC} 2] C - B  3] B - C 4] { B - C }'
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CBSE 11-science - Maths
I am confused in a question from SETS AND RELATIONS P(A:B)={X:X∈P(A),B⊂X} In the given statement, does P(A:B) mean power set of ratio of set A and B? Please correct me if I am going wrong because I am not sure about it.
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CBSE 11-science - Maths
Does the set S={0,1,-1} form a group under multiplication?
Asked by arjunsah797 | 03 Mar, 2022, 06:04: PM
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CBSE 11-science - Maths
PLEASE ANSWER THIS QUESTION ON SETS! 👇
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Asked by krishkhare04 | 03 Feb, 2022, 02:35: PM
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