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CBSE Class 11-science Answered

26th sum
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Asked by lovemaan5500 | 31 Jan, 2019, 11:35: AM
answered-by-expert Expert Answer
Since in both cases the particle is moving with constant velocity. So the centripetal acceleration will remain constant in both case and it's value would be v^2/r
=10^2/5=100/5= 20 m/s^2.
Answered by Ankit K | 31 Jan, 2019, 12:49: PM
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CBSE 11-science - Physics
Hi
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