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CBSE Class 11-science Answered

25g of a solute of molar mass 250g/molecular is dissolved in 100ml of water to form a. Solution whose density is 1.25 g/ml. The molality is? ( answer =0.8) please solve it . 
Asked by govtsecschoolnayaganv051 | 16 Jan, 2019, 09:07: PM
answered-by-expert Expert Answer
Given:
 
Weight of solute = 25 g
 
Molar mass of solute = 250 g/mole
 
Volume of solvent = 100 ml
 
Density of water = 1 g/ml
 
We know that,
 
Density space equals fraction numerator Mass space over denominator volume space end fraction

Mass space equals space density space cross times space volume

space space space space space space space space space space equals space 1 cross times 100

space space space space space space space space space space equals space 100 space gm

Molality space equals space fraction numerator No. space of space moles space solute over denominator Weight space of space solvent space left parenthesis straight H subscript 2 straight O right parenthesis end fraction

space space space space space space space space space space space space space space equals fraction numerator 0.1 over denominator 0.1 end fraction

Molality space space equals space 1 space straight m
 
 
Molality of the solution is 1 m.
Answered by Varsha | 17 Jan, 2019, 11:53: AM
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