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CBSE Class 11-science Answered

23?
question image
Asked by smanishkumar2002 | 04 Aug, 2018, 08:36: PM
answered-by-expert Expert Answer
x2 + xy - 6y2 = 0
Solving we get
(x + 3y)(x - 2y) = 0
x + 3y = 0 and x - 2y = 0
Find the perpendicular distance from (1, 1) to both the liens we get 
begin mathsize 16px style fraction numerator 4 over denominator square root of 10 end fraction space and space fraction numerator 1 over denominator square root of 5 end fraction end style find the product of this we get begin mathsize 16px style fraction numerator 2 square root of 2 over denominator 5 end fraction end style
Answered by Sneha shidid | 06 Aug, 2018, 11:23: AM

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