ICSE Class 10 Answered
22 ques
Asked by lovemaan5500 | 26 Nov, 2017, 12:43: PM
Expert Answer
Heat energy required to melt the ice of mass 150 g = 150 × Latent Heat of Ice = 150 × 336 Joules
Heat energy lost by Steam of mass ms from 100°C vapour state to 100°C Liquid state = ms × Latent Heat of Steam = ms × 2260 Jouls
ms = (150 × 336 ) / 2260 = 22.3 g
Total mass of water = 150+30+22.3 = 202.3 g
Answered by | 27 Nov, 2017, 03:00: PM
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