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Asked by lovemaan5500 25th September 2018, 6:58 PM
Answered by Expert
Answer:
Centripetal force experienced by the moon when it revolving around earth = m×ω2×R ....................(1)
 
where m is mass of moon, ω is angular speed, R is mean distance from earth.
 
Centripetal acceleration = ω2×R = ω2×60×RE = ( 4π2/T2 )×60×RE .........................(2)
 
where RE is earth's radius. T is time period for one revolution around earth which is 27.3 days
 
Centripetal acceleration = begin mathsize 12px style equals space fraction numerator 4 pi squared cross times 60 cross times 6371 cross times 1000 over denominator open parentheses 27.3 cross times 24 cross times 60 cross times 60 close parentheses squared end fraction space equals space 2.712 cross times 10 to the power of negative 3 end exponent end style m/s2 .....................(3)
we compare the centripetal acceleration calculated in eqn.(3),  i.e 9.8 / (2.712×10-3 ) = 3614
Answered by Expert 26th September 2018, 10:28 AM
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