CBSE Class 11-science Answered
20th sum
Asked by lovemaan5500 | 25 Sep, 2018, 07:04: PM
Expert Answer
Stokes formula is given by, 6π×a×η×v = m×g...............(1)
where a is radius of drop, η is coeff of viscosity, v is terminal velocity,
m is mass of drop and g is acceleration due to gravity.
Clubbing together all constants, we rewrite eqn.(1) as, a×v = K×m ..............(2)
Let v' be the terminal velocity for the coaleased drop.
For coaleased drop, mass will be doubled and new radius will be as explained below, if a is the radius of original drop.
from eqn.(2) we write, .......................(3)
from eqn.(3), we have
Answered by Thiyagarajan K | 25 Sep, 2018, 10:42: PM
CBSE 11-science - Physics
Asked by sheikhsaadat24 | 17 Apr, 2024, 09:41: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by sy123946 | 07 Apr, 2024, 04:23: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by derhebha955 | 03 Apr, 2024, 09:03: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by sumedhasingh238 | 29 Mar, 2024, 05:15: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by sumedhasingh238 | 28 Mar, 2024, 11:10: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by roshnibudhrani88 | 23 Mar, 2024, 05:52: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by emad.amd | 21 Mar, 2024, 12:00: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by vinitdubey7735 | 14 Mar, 2024, 11:21: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by om636694 | 04 Mar, 2024, 09:10: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by rajuinwati12 | 04 Mar, 2024, 09:22: AM
ANSWERED BY EXPERT