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2.05 molarity acetic acid solution is having density 1.02g/cm3. Find molality of the solution if molecular mass of the acetic acid is 60g.
Asked by defence | 09 May, 2019, 09:28: PM
answered-by-expert Expert Answer
Given:
 
Molarity of solution = 2.05 M
 
Density = 1.02 g/cm3 
 
Molecular mass of acetic acid = 60 g
 
Volume of solution = 1 litre
 
 
Weight space of space acetic space acid space equals space 2.05 cross times 60 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 123 space straight g Weight space of space solution space equals space 1.02 cross times 1000 space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 1020 space straight g therefore space Weight space of space water space in space solution space equals space 1020 space minus 123 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 897 space straight g space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 0.897 space kg Now comma Molality space equals space fraction numerator 2.05 over denominator 0. space 897 end fraction space space space space space space space space space space space space space equals space 2.28 space straight m
Molality of solution is 2.28 m.
Answered by Varsha | 10 May, 2019, 11:06: AM

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