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()2-Butanol is optically inactive. Why?

Asked by Shrawani Misra 13th March 2013, 8:16 PM
Answered by Expert
Answer:

2-Butanol is chiral and thus can be obtained as either of two stereoisomers designated as (R)-(?)-2-butanol and (S)-(+)-2-butanol.

It is normally found as an equal mixture of the two stereoisomers a racemic mixture. As we know a racemic misture is optically inactive, so, ()2-Butanol is optically inactive.

Answered by Expert 16th March 2013, 6:34 AM
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