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CBSE Class 11-science Answered

1.How to find equation of parabola whose directrix is y=-x 2.how to find equation of an ellipse whose foci is at (2,2)
Asked by Kidistye | 04 Feb, 2019, 02:29: AM
answered-by-expert Expert Answer
(1) Parabola question
 
Let S(h,k) be the focus of parabola and P(x1 , y1) be any point on parabola
 
if PN is perpendicular line drawn from P to directrix, we have  SP = NP
 
hence begin mathsize 12px style square root of open parentheses x subscript 1 minus h close parentheses squared space plus space open parentheses y subscript 1 minus k close parentheses squared end root space equals space fraction numerator x subscript 1 plus y subscript 1 over denominator square root of 2 end fraction end style
By squaring both sides, begin mathsize 12px style space open parentheses x subscript 1 minus h close parentheses squared space plus space open parentheses y subscript 1 minus k close parentheses squared space equals space 1 half open parentheses x subscript 1 plus y subscript 1 close parentheses space end style
By dropping suffix, we get the required equation : begin mathsize 12px style space open parentheses x minus h close parentheses squared space plus space open parentheses y minus k close parentheses squared space equals space 1 half open parentheses x plus y close parentheses space end style
-------------------------------------------------
 
For ellipse, only one focus point is given in the question,  another focus point and additional information about axiis length
is required to solve the question
Answered by Thiyagarajan K | 06 Feb, 2019, 09:22: PM

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