ICSE Class 10 Answered
1.5 kg of ice melts when a jet of steam at 100 degree C is passed in an ice block .Calculate the mass of steam required to achieve it
Asked by lovemaan5500 | 29 Dec, 2017, 06:39: AM
Expert Answer
Let MS be the required mass of steam in kg.
Heat loss by the steam from 100°C to 0C is, QL = MS×Lv+MS×Cp×(100-0)
where Lv is latent heat of vaporaisation of steam, Cp is specific heat of water
Heat required to Melt 1.5 kg of ice, QG = 1.5×Lf
where Lf is latent heat of vaporaisation of steam
QL = QG
MS×Lv+MS×Cp×(100-0) = 1.5×Lf
MS = 1.5 × [ Lf / ( Lv + 100 × Cp ) ]
Lf = 334 kJ/kg, Lv = 2260 kJ/kg and Cp = 4.2 kJ/(kgK)
MS = ( 1.5×334 ) /2680 = 187 gm
Answered by | 29 Dec, 2017, 12:37: PM
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