Ask a Doubt
Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 11-science Answered

14th?
question image
Asked by smanishkumar2002 | 04 Aug, 2018, 05:41: AM
answered-by-expert Expert Answer
Here we have two cases 
 
Case I
Given :
P= 1 atm
w= 24 g
T = (t+273)K
V = V litre
 
Using the gas equation,
PV space equals space straight w over straight m space RT 1 space cross times space straight V space equals space 24 over straight m space straight R space left parenthesis straight T space plus space 273 right parenthesis.............................. left parenthesis 1 right parenthesis
 
Case II:
Given:
T = (T + 283)K
 
P = 1 plus fraction numerator 20 over denominator 100 space end fraction equals space 1.2 space atm
w = 24 g 
 
V= V Litre
 
Using the gas equation,
PV space equals space straight w over straight m space RT 1.2 space cross times space straight V space equals space 24 over straight m space straight R space left parenthesis straight T space plus space 283 right parenthesis.............................. left parenthesis 2 right parenthesis
 
By equating equation (1) and (2)
 
fraction numerator 1.2 over denominator 1 end fraction space equals fraction numerator left parenthesis T space plus 283 right parenthesis space over denominator left parenthesis T space plus 273 right parenthesis end fraction therefore space 1.2 space T space plus space 327.6 space equals space T space plus space 283 0.2 T space equals space minus 44.6 T space equals space minus 223 degree C space equals space 50.15 K A l s o space F r o m space left parenthesis 1 right parenthesis comma space o n space s u b s t i t u t i n g space t space a n d space m equals 120 space w e space g e t space 1 space cross times space V space equals space fraction numerator 24 over denominator 120 space end fraction cross times 0.082 cross times 50.15 V space equals space 0.82 space l i t r e
Answered by Ramandeep | 06 Aug, 2018, 11:57: AM

Concept Videos

Multiple Choice Questions Practice Test
Answered Unanswered My Questions My Answers
CBSE 11-science - Chemistry
Find volume occupied by 1 molecule of He (g) at STP.
Asked by jayag1298 | 08 Apr, 2024, 03:14: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Chemistry
what volume of 0.2 M sulfuric acid is required to neutralize 25ml of 0.1 NaOH solution?
question image
Asked by omniscientnjf2021 | 07 Apr, 2024, 10:18: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Chemistry
1 mol of ferric oxalate is oxidised by x mol of MnO4​−  and also one mol of ferrous oxalate is oxidised by y mol of  MnO4​− in acidc medium . ratio x/y is ? answer in simple words pleasee
question image
Asked by hcnainwal | 15 Jun, 2023, 10:39: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Chemistry
convert 5.6g/cm3 into kg/m³
Asked by Jprmumal29 | 18 Dec, 2022, 09:48: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Chemistry
0.315g of organic compound gave on combustion 0.4131g of water and 0.6732g of carbon dioxide calculate the percentage of carbon and hydrogen
Asked by mallikarjunasangi28 | 22 Jul, 2022, 07:57: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Chemistry
IS ALL PHYSICAL QUANTITIES WHICH ARE MEASUREBLE ARE MATTER OR NON MATTER?
Asked by vedwatisharma79 | 10 Jun, 2022, 05:27: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Chemistry
0.38g of NaOH is dissolved in water to prepare 50 ml solution. calculate the molarity of the solution
Asked by thathvakunjusree | 10 Dec, 2021, 06:46: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Chemistry
molecular mass
Asked by udheshraddha2004 | 28 Oct, 2021, 09:37: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Chemistry
324g of 20% by mass of Ba(OH)2 solution
question image
Asked by arunparewa2000 | 27 Oct, 2021, 06:59: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Chemistry
what is molecular mass?
Asked by arttameher038 | 23 Aug, 2021, 07:06: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
My Class Videos Tests ₹ Plans Ask a Doubt
Get Latest Study Material for Academic year 24-25 Click here
×