Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
8104911739
For Business Enquiry

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

122.5 g of h2so4 are dissolved in water to make 1250 ml of solution. the concentration in normality is 

Asked by Roopam 12th June 2019, 5:39 PM
Answered by Expert
Answer:
Given:
 
Weight of H2SO4 = 122.5 gm
 
Volume = 1250 ml
 
Molar mass of H2SO4 = 98.07  gm/mol
 
No. of moles 
equals fraction numerator Weight over denominator mol. space weight end fraction

space equals space fraction numerator 122.5 over denominator 98.07 end fraction

equals 1.2 space mol
 
Now,
 
Molarity v
equals space fraction numerator No. space of space mole over denominator Volume space of space solution space in space straight L end fraction

equals space fraction numerator 1.249 over denominator 1.250 end fraction

equals 1 space straight M
 
Normality = Molarity × No. of H+ ions
 
               = 1×2 2 N
 
Therefore the normality of the solution is 2N.
Answered by Expert 13th June 2019, 10:52 AM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Latest Questions

ICSE VII Chemistry
Asked by ranju18sharma1997 15th September 2019, 6:05 PM
ICSE VIII Physics
Asked by Shivamanidaffodils 15th September 2019, 5:52 PM
CBSE VII Mathematics
Asked by punu2003 15th September 2019, 5:35 PM

Chat with us on WhatsApp