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# 114

Asked by dunnanagamani02 30th May 2021, 8:07 AM
Qn.120

NOR gate output is followed by two inverter because NAND gate is connected as inverter.

Hence equivalent circuit is NOR gate

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Qn.121

Magnetic field induction B at centre of loop of radius R is given as

.................... (1)
where I is current in the loop and μo is the permeability of free space .

When helium nucleus that has charge 2e is moving with speed v in a circular loop ,

current I = ( 2e v ) = ( 2e ) × [ ( 2 π R ) / T ]  ....................(2)

where T = 2 s is period of revolution

If we substitute current I using eqn.(2) , we get magnetic field from eqn.(1) as

T
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Qn.122

Magnetic field at centre of loop has two parts , (i) one part due to long wire carrying current I  and
(ii) second part due to current  I in circular loop

Magnetic field due to long wire ,
Magnetic field due to circular loop ,
Net magnetic field ,
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Qn. 123

Let charge on particle-X = q and charge on particle-Y = 2q

Kinetic energies of particles after accelerated by same potential difference V is given as

.................... (1)
....................(2)
From above equations (1) and (2) , we get     ......................(3)
In magnetic field , magnetic force equals centripetal force . Hence we have

...........................(4)
........................ (5)
From above equations (4) and (5) we get  ....................(4)
By equating eqn.(3) and (4) , after simplification, we get
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If multiple questions are posted in one posting  and question to be solved is not specified,
we do not solve all the questions.

post only one question in one posting.

Answered by Expert 30th May 2021, 2:49 PM
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