CBSE Class 11-science Answered

Let the volume of CH₄ = x ml and volume of C₂H₄ = y ml

Hence volume of CO₂ = (10 - x - y) ml

Since after the explosion, there was contraction of 17ml; this means that when the explosion takes place at that time water is in gaseous state, after the explosion water vapours converted into liquid state and the volume of liquid water is assumed to be zero.

Hence 2x + 2y = 17………………..     (a)

Since KOH absorbs CO₂ gas when the gaseous mixture is treated with KOH further reduction in volume is 14 ml, hence volume of CO₂ in gaseous mixture is 14 ml.

10 - x - y + x + 2y = 14…………….. (b)

10 + y = 14

Y = 4 ml

On putting this value in equation (a), we get

 x = 4.5

So, volume of CH₄ = 4.5 ml

Volume of C₂H₄ = 4 ml

Volume of CO₂ = (10 - 4 - 4.5) = 1.5 ml