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CBSE Class 10 Answered

1)Three consecutive positive integers are such that the sum of the squares of the first and the product of the other two is 46, find the integers.    
Asked by hsradha75 | 25 Feb, 2019, 11:09: PM
answered-by-expert Expert Answer
Let three numbers be (x-1), x and (x+1)
 
Given :  (x-1)2 + x (x+1) = 46
 
2x2 -x + 1 = 46   or    2x2 -x -45  = 0    
 
LHS can be factorised and written as, (2x+9)(x-5) = 0   or  x = 5
 
Hence numbers are, 4, 5 and 6
 
Answered by Thiyagarajan K | 26 Feb, 2019, 10:02: AM

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