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# 1 g mixture of CaCO3 and NaCl reacts completely with 100 ml of N/10 HCl. The % of CaCO3 in the mixture is-(1) 40%, (2)60%, (3) 50%, (4) 80%. Also mention which is to be taken as Solute, HCl or CaCO3??

Asked by patra04011965 7th August 2019, 8:57 PM
Answered by Expert
Answer:
Option (3) is correct: 50%

Given:

Mass of CaCO3 + NaCl = 0.1 gm

Volume of HCl = 100 ml

Normality of HCl = 0.1 N

Molarity of HCl = 0.1 M

Molar masss of  CaCo3 = 100 g/mol

HCl reacts with CaCo3. The reaction is written as,

CaCo3 + 2HCl  → CaCl2 + CO2 +H2O

1 mole of CaCo3 reacts with 2 moles of HCl

No. of moles of HCl is

Now moles of CaCo3 can be calculated as,

Moles of  CaCo3

Mass of  CaCo3 is calculated as,

No. of moles =

Mass of  CaCo3 = No. of moles × Molar mass of  CaCo3

= 0.005×100

= 0.5 gm

Percentage of CaCo3 = 0.5 × 100

= 50 %
Answered by Expert 8th August 2019, 11:04 AM
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