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1) Factorise by using middle term splitting

83 + 27y+ z3 _ 18yz

2) Find

(783)2/3

Please explain step-by-step.

use cubic algebraic identities

Asked by stutagra 26th May 2016, 4:36 PM
Answered by Expert
Answer:
1 right parenthesis
8 cubed plus 27 y cubed plus z cubed minus 18 y z
equals 2 cubed plus open parentheses 3 y close parentheses cubed plus z cubed minus 3 open parentheses 2 close parentheses open parentheses 3 y close parentheses open parentheses z close parentheses
equals open parentheses 2 plus 3 y plus z close parentheses open parentheses 2 squared plus open parentheses 3 y close parentheses squared plus z squared minus 2.3 y minus 3 y. z minus 2 z close parentheses
equals open parentheses 2 plus 3 y plus z close parentheses open parentheses 2 squared plus 9 y squared plus z squared minus 6 y minus 3 y z minus 2 z close parentheses

2 right parenthesis
783 equals 3 cubed cross times 29
783 squared equals 3 to the power of 6 cross times 29 squared
open parentheses 783 squared close parentheses to the power of 1 divided by 3 end exponent equals 3 to the power of 6 divided by 3 end exponent cross times 29 to the power of 2 divided by 3 end exponent
equals 3 squared cross times 29 to the power of 2 divided by 3 end exponent
Answered by Expert 29th May 2016, 4:24 PM
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