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1.    An object weighs 400 N in air and 200 N in water. What is the weight of the water displaced by the object and calculate its relative density.

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1.    An object weighs 400 N in air and 200 N in water. What is the weight of the water displaced by the object and calculate its relative density.

Asked by Devika PC 25th February 2015, 8:05 PM
Answered by Expert
Answer:

weight of object in air = 400 N

weight of object in water = 200 N

Weight of water displaced = weight of object in air – weight of object in water

Weight of water displaced  = 400 - 200 = 200 N

Therefore, the weight of the object displaced by the object is 200 N

begin mathsize 12px style Relative space density space of space object space equals space fraction numerator Weight space of space the space object space in space air over denominator Loss space of space weight space of space object space in space water space end fraction space equals space fraction numerator 400 over denominator left parenthesis 400 space minus space 200 right parenthesis end fraction space rightwards double arrow straight R. straight D. space equals space 400 over 200 space equals space 2 end style

Hence, the relative density of object is 2.

Answered by Expert 26th February 2015, 9:22 AM
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