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CBSE Class 11-science Answered

1. A rectangular plateof dimensions 6*4 and thickness 2mm is placed with its largest face flat on the surface of water. Find the downward force on the plate due to surface tension, surface tension of water is 7*10^-2.
2. I f the normal density of sea wateris 1.00g/cm, what will be its density at a depth of 3km?
Given, compressibility of water=0.000048 per atmosphere, 1 atmospheric pressurre= 1.01*10^6 dyne/cm^2
Asked by Nirbhay | 06 Nov, 2014, 09:26: AM
answered-by-expert Expert Answer
Please ask different questions as separate queries.
 
W e space k n o w space t h a t comma D e n s i t y comma space rho space equals space m over V D e n s i t y space a t space d e p t h space 3 k m comma space rho apostrophe equals space fraction numerator m over denominator V minus v end fraction H e r e comma space v space i s space t h e space d e c r e a s e space i n space v o l u m e space o f space t h e space s a m e space m a s s space w h e n space t a k e n space t o space t h e space b o t t o m. N o w comma space fraction numerator rho over denominator rho apostrophe end fraction equals m over V cross times fraction numerator V minus v over denominator m end fraction equals space 1 space minus space v over V B u t comma space K space equals space fraction numerator begin display style fraction numerator increment p over denominator v end fraction end style over denominator V end fraction space o r space v over V equals space fraction numerator increment p over denominator K end fraction T h e r e f o r e comma space space fraction numerator rho over denominator rho apostrophe end fraction equals space 1 space minus space fraction numerator increment p over denominator K end fraction space equals space 1 space minus space open parentheses 1 over K close parentheses increment p o r comma space fraction numerator rho over denominator rho apostrophe end fraction equals space 1 space minus space open parentheses 0.000048 space a t m to the power of minus 1 end exponent close parentheses space cross times space 3 space cross times space 10 to the power of 5 space cross times 980 o r comma space rho apostrophe space equals space fraction numerator rho over denominator 0.98603 end fraction o r comma space space rho apostrophe space equals space space 1.014 space g c m to the power of minus 3 end exponent
Answered by Sheetal Jalan | 07 Nov, 2014, 08:39: AM
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CBSE 11-science - Physics
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