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ICSE Class 10 Answered

[1] A cell of e.m.f. 1.5 V and internal resistance 1.0 is connected to two  resistors of 4.0 and 20.0 in a series Calculate the: (i)Current in the circuit. (ii)Potential difference across the 4.0 ohm resistor. (iii)Voltage drop when the current is flowing. (iv)Potential difference across the cell. [2] Explain  why  alpha  and  beta-particles  are  deflected  in  an  electric   or  a magnetic field but gamma rays are not deflected in such a field.   [3] A  transmission  line  having  a  total  resistance  of  0.2 delivers 10   kW  at  220  V  to  a small factory. Calculate the power loss in the line.  Temperature  of  a  solid  body  is  observed  to  be  constant  during  aperiod.  Give  two inferences for this period.
Asked by Farheen1447 | 04 Mar, 2019, 11:30: PM
answered-by-expert Expert Answer
Q.(1)  
Current in the circuit   = 1.5 / (1+4+20) = 1.5 / 25 = 0.06 A  = 60 mA
 
Voltage across 4Ω resistor = 4×0.06 = 0.24 V
 
Voltage drop due to internal resistance 1Ω = 1×0.06 = 0.06 V
 
potential difference across the cell = 1.5 - 0.06 = 1.44 V
 
Q(2) α-ray consists of particle which is positively charged helium nucleus .
β-ray consists of negatively charged electron  .
Due to the associated charges,  α-ray and β-ray are subjected to electric and magnetic force and get deflected.
Whereas γ-ray is neutral electromagnetic radiation. Hence γ-ray is not deflected by electric and magnetic field.
 
Q(3)
current passing through transmission line = ( 10×1000)/220 = 500/11 ≈ 45 A
power loss in transmission line = i2R = (500/11)×(500/11)×0.02 ≈ 413 W
Answered by Thiyagarajan K | 05 Mar, 2019, 08:19: AM
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