ICSE Class 10 Answered
[1] A cell of e.m.f. 1.5 V and internal resistance 1.0 is connected to two
resistors of 4.0 and 20.0 in a series Calculate the:
(i)Current in the circuit.
(ii)Potential difference across the 4.0 ohm resistor.
(iii)Voltage drop when the current is flowing.
(iv)Potential difference across the cell.
[2] Explain why alpha and beta-particles are deflected in an electric
or a magnetic field but gamma rays are not deflected in such a field.
[3] A transmission line having a total resistance of 0.2 delivers 10
kW at 220 V to a small factory. Calculate the power loss in the line.
Temperature of a solid body is observed to be constant during aperiod.
Give two inferences for this period.
Asked by Farheen1447 | 04 Mar, 2019, 11:30: PM
Expert Answer
Q.(1)
Current in the circuit = 1.5 / (1+4+20) = 1.5 / 25 = 0.06 A = 60 mA
Voltage across 4Ω resistor = 4×0.06 = 0.24 V
Voltage drop due to internal resistance 1Ω = 1×0.06 = 0.06 V
potential difference across the cell = 1.5 - 0.06 = 1.44 V
Q(2) α-ray consists of particle which is positively charged helium nucleus .
β-ray consists of negatively charged electron .
Due to the associated charges, α-ray and β-ray are subjected to electric and magnetic force and get deflected.
Whereas γ-ray is neutral electromagnetic radiation. Hence γ-ray is not deflected by electric and magnetic field.
Q(3)
current passing through transmission line = ( 10×1000)/220 = 500/11 ≈ 45 A
power loss in transmission line = i2R = (500/11)×(500/11)×0.02 ≈ 413 W
Answered by Thiyagarajan K | 05 Mar, 2019, 08:19: AM
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