CBSE Class 11-science Answered
0.92 g of Ag2CO3 is heated strongly beyond its melting point. After heating the amount of residue is
Asked by Anil | 17 May, 2017, 03:04: PM
Expert Answer
Ag2CO3 (s) → 2Ag (s) + CO2 (g) + 1/2 O2 (g)
Molecular Weight = 276g 2 × 108 = 216 g
Hence, 0.92 g of Ag2CO3 on heating will give
216/276× 0.92 = 0.72 g Ag as residue.
Answered by Vaibhav Chavan | 17 May, 2017, 03:14: PM
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