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0.17g of ammonia on decomposition gave 0.14g of nitrogen and rest hydrogen . What will be the volume of hydrogen evolved at S.T.P
Asked by Imsneharose | 30 Nov, 2021, 09:34: PM
answered-by-expert Expert Answer

2NH3 → N2 + 3H2


Moles of NH3 present = 0.17 g x 1 mol/17 g = 0.01 moles 


moles H2 produced = 3/2 x 0.01 moles = 0.015 moles H2 


At STP 1 mole = 22.4 L

 

So volume of H2 = 0.015 moles x 22.4 L/mol = 0.336 Liters. 

Answered by Ramandeep | 01 Dec, 2021, 06:19: PM

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